Question

2. Two masses m1, and m2 are connected of
light string
. The string passes over
a smooth frictionless pully. calculate
The acceleration of the masses
and the tension in a
string
​

Answer 1

Answer:

hope this is the answer

Answer 2

Explanation:

Remember here, m1 > m2

For mass m2, the forces are given as

$T - m_{2} g = m_{2} a ..........(1)$

Similarly, for mass m1, the forces are given as\

$m_{1} g - T = m_{1} a ............(2)$

From equation (1), we have

$T = m_{2} g + m_{2}a ..........(3)$

Substituting equation (3) in (2) we get

$(m_{1} - m_{2})g = (m_{1} + m_{2})a\\ a = (m_{1} - m_{2})g/(m_{1} + m_{2}).........(Acceleration)\\T = m_{2}(m_{1} - m_{2})g/(m_{1} + m_{2}) + m_{2}g\\T = g(2m_{1}m_{2})/(m_{1} + m_{2})...............(Tension)$

(I hope it will be marked as Brainliest)