Question

2. Two metallic conductors have net charges of 70PC & - 70 pC, which results in a potential difference of 20V b/w them. What is the capacitance of system?

Answer 1

Answer:

Charge= 70 pC=70*10¹² C

PD=20V

Capacitance= q/V=70*10¹²/20

=35*10¹²=35pF