Question

2. Two numbers are in the ratio 4: 7. If thrice the
larger be added to twice the smaller, the sum is
59. Find the numbers.​

Answer 1

Answer:

Step-by-step explanation:

Let the numbers be 4x : 7x

Given, 3(7x)+2(4x)=59

⇒21x+8x=59

29x=59

⇒x =  $\frac{59}{29}$

Thus the numbers are 4x = 4× $\frac{59}{29}$ = $\frac{236}{29}$ = 8$\frac{4}{29}$

​and 7x = 7 × $\frac{59}{29} = \frac{413}{29} = 14\frac{7}{29}$  

Answer 2

Let the number be 4x;7x

Given ,3(7x) + 2(4x) = 59
➜ 21 x+ 8 x = 59
29x = 59
➜ x = $\frac{59}{29}$
Thus the numbers are
[tex] 4x = 4 * \frac {59}{29} = {236}{29} = 8 {4}{29}
And 7x = 7* 59/29 = 413/29
➜= 14 7/29