Question

2.Two point charges 3C and 4C at a distance from each other are experiencing a repulsive force of 10 N between them . If -6C is added to both the charges , what would be the new force between them?​

Answer 1

Answer:

5N

Explanation:

$charge \: q_{1} = 3c \\ charge \: q_{2} = 4c \\ force = \frac{k \times 3 \times 4}{ {d}^{2} } \\ 10 = \frac{12k}{ {d}^{2} } \\ {d }^{2} = \frac{12k}{10} \: \: \: \: \: \: (1) \\ \\ force = \frac{k(3 - 6)(4 - 6)}{ \frac{12k}{ {d}^{2} } } \\ = \frac{6k}{ \frac{12k}{ {d}^{2} } } \\ = \frac{1}{2} \times 10 \\ = 5 \: newton$

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