Question

2. Two point charges +8q and -2q are located at x=0 and x=L respectively. The point on x axis at which net electric field is zero due to these charges is- (a) 8L (b) 4L (c)2 L (d) L
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Answer 1

Answer:

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Answer 2

Answer:

2L

Explanation:

(-k2q)÷(x-L²) + k8q÷(x²) =0

1÷(x-L)² = 4÷x²

Which implies 1÷(x-L) = 2x -2L

Therefore x = 2L