Question

2. Two sides of a triangle are 6 cm and 8 cm. If
height of the triangle corresponding to 6 cm
side is 4 cm; find :
(i) area of the triangle
(ii) height of the triangle corresponding to 8cm side.

the answers are
(i)

$12cm {}^{2}$




(ii)
3cm

I have given the answers above the chapter is mensuration area of a Trapezium and a polygon please do in class 8th standard explain the method and solve it. only solve if you know otherwise don't solve thank you .​ don't give me any reply If you are going to write rubbish ​

Answer 1

$\sf\underbrace{\red{SOLUTION:-}}$

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☞ See the attachment diagram .

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GIVEN :-

Here,

• AC = 6 cm
• Height corresponding to AC is “BE” = 4cm

• BC = 8 cm
• Height corresponding to BC is “AD” = ?

FORMULA :-

$\checkmark\:\sf\underline{\purple{\boxed{Area\:of\:Triangle\:=\:{\dfrac{1}{2}}\:\times{base}\:\times{height}\:}}}$

CALCULATION :-

• AC = 6 cm
• BE = 4 cm

☞ So, Area of triangle is,

$\sf{=\:{\dfrac{1}{2}}\:\times{AC}\:\times{BE}\:}$

$\sf{=\:{\dfrac{1}{2}}\:\times{6}\:\times{4}\:}$

$\sf{=\:12\:{cm}^{2}\:}$

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• BC = 8 cm
• AD = ?

☞ Again, Area of triangle is,

$\sf{=\:{\dfrac{1}{2}}\:\times{BC}\:\times{AD}\:}$

$\sf{\implies\:12\:cm^{2}\:=\:{\dfrac{1}{2}}\:\times{8}\:\times{AD}\:}$

$\sf{\implies\:{AD}\:=\:3\:cm\:}$

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(i) Area of triangle is “12 cm²” .

(ii) Height of the triangle corresponding to 8cm side is “3 cm” .