2 Two towers are 150 m apart. The angle of elevation of the top of the first tower as
seen from the top of the second tower is 30" Find the height of the
a) First tower, when the second tower is 120 m high
b) Second tower, when the first tower is 140m high
Answers
Given : Two towers are 150 m apart.
The angle of elevation of the top of the first tower as seen from the top of the second tower is 30°
To : Find the height of the
a) First tower, when the second tower is 120 m high
b) Second tower, when the first tower is 140m high
Solution:
Let say h is the height of first tower more than tower 2
Tower 1 height = tower 2 height + h
d = horizontal distance between towers = 150 m
Tan 30° = h / d
=> 1/√3 = h / 150
=> h = 50√3
=> h = 86.6 m taking √3 = 1.732
height of the First tower, when the second tower is 120 m high
= 120 + 86.6
= 206.6 m
height of the Second tower, when the first tower is 140m high
= 140 - 86.6
= 53.4 m
learn More:
From the top of a cliff of height h metre the angles of depression of ...
brainly.in/question/20277496
From top of a small hill,the base of a vertical cliff has an angle of ...
brainly.in/question/17473853
Two men are standing on either side of a cliff 100 m high observe ...
brainly.in/question/14780958