2. Two vertices of a triangle are (1, 3) and (4,7). The
orthocentre lies on the line x + y = 3. The locus of the third
vertex is
(a) -217 + 2y - 3x - 4y + 36 = 0
(6) 21² - 401 + 3y² - 4x - y + 42 = 0
(c) 3r+ry - 412-21 + 24y - 40 = 0
(d) - 4.7y + 3y2 - 2x - y + 40 = 0
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Answer:
(c)3r+ry-412-21+24y-40
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