Question

2 two years ago a man was five times as old his son 2 years later his age will be eat more than three times the age of his son find their present

please answer me fast and explain​

Answer 1

Let the age of father is x years and that of son is y years.

Then by the given question,

x-2=5(y-2)

or, x-5y=-10+2

or, x-5y=-8

or, x=5y-8

x+2=3(y+2)+8

or, x-3y=6+8-2

or, 5y-8-3y=12

or, 2y=12+8

or, y=20/2

or, y=10

then x=5y-8=50-8=42

Then, the age of father is 42 yrs. and the age of sun is 10 yrs.

Plz plz plz mark as brain list.

Answer 2

Answer:

Let father age be x, his son age be y.

Before 2 years,

⇒(x−2)=5(y−2)−−−−−−−(1)

After 2 years

⇒(x+2)=8+3(y+2)−−−−−−−−(2)

From (1) x−5y+8=0

From (2)

⇒x+2−3y−6−8=0

⇒x−3y−12=0

Solving them

⇒−2y+20=0

⇒y=10

When y=10,x=42

So the present age of the father is 42 and the son age is 10.