Question

2. Two years ago, father was three times as old as his son and two years hence,
his age will be equal to five times that of his son. Find their present ages.
​

Answer 1

Answer:

Let the present age of son = x

Two years ago, age of son = x - 2

Two years ago, age of father = 3(x - 2)

So, the present age of Father = 3(x - 2) + 2 = 3x - 6 + 2 = 3x - 4

Two years hence, age of father =3x - 4 + 2 = 3x - 2

Two years hence , age of son = x + 2

According to question,

5(x + 2) =2(3x - 2)

=> 5x + 10= 6x - 4

=> 10 + 4 = 6x - 5x

=> 14 = x

So, the present age of son = x = 14 years

And the present age of father = 3x - 4 = 3 * 14 - 4 = 42 - 4 = 38 years

Step-by-step explanation:

mark as brainlist