Question

2+under root 3 by 2-under root 3 + 2-under root 3 by 2+ under root 3

Answer 1

Answer:

Step-by-step explanation:

$\frac{2+\sqrt{3}}{2-\sqrt{3}}+\frac{2-\sqrt{3}}{2+\sqrt{3}}\\= \frac{(2+\sqrt{3})^2+(2-\sqrt{3})^2}{(2+\sqrt{3})(2-\sqrt{3})}\\=\frac{4+2\sqrt{3}+3+4-2\sqrt{3}+3}{2^2-\sqrt{3}^2}\\=\frac{14}{4-3}\\=14$

please click on thanks and rate 5 star

peace!