Question

2.
Use Euclid division lemma to show that any positive odd integer is of the form 6q+1, or
69 + 3 or 69 + 5, where q is some integers.​

Answer 1

Step-by-step explanation:

it is solutions for u r answer ok then

Answer 2

Answer:

Let

′

a

′

be any positive integer and b=6

Then by division algorithm

a=6q+r where r=0,1,2,3,4,5

so, a is of the form 6q or 6q+1 or 6q+2 or 6q+3 or

6q+3 or 6q+4 or 6q+5

Therefore If s is an odd integer

Then

′

a

′

is of the form 6q+1 or 6q+3 6q+5

Hence a positive odd integer is of the form 6q+1 or 6q+3 or 6q+5