Question

2. Use multiplication to find the factors of the following.
(a) 48
(b) 55
(c) 42​

Answer 1

Answer:

a)

1 × 48 = 48

2 × 24 = 48

3 × 16 = 48

4 × 12 = 48

6 × 8 = 48

b)

1 × 55 = 55

5 × 11 = 55

c)

1 × 42 = 42

2 × 21 = 42

3 × 14 = 42

6 × 7 = 42

Step-by-step explanation:

factors of 48= 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

factors of 55= 1, 5, 11, 55

factors of 42= 1, 2, 3, 6, 7, 14, 21, 42

Answer 2

Given:

48 ,55 , 42

To find:

The factors

Solution:

• A number that divides another number exactly without any remainder is called factor.(eg: 10÷5 = 2)
• Here 5 and 2 are factors of 10.

(a) 48

       1×48 = 48

      2×24 = 48

      3×16 = 48

      4×12 = 48

      6×8 = 48

So the factors of 48 : 1,2,3,4,6,8,12,16,24,48.

(b) 55

      1×55 = 55

      5×11 = 55

      11×5 = 55

So the factors of 55 : 1,5,11,55.

(c) 42

      1×42 = 42

      2×21 = 42

      3×14 = 42

      6×7 = 42

 So the factors of 42 :1,2,3,6,7,14,21,42