Question

2. Use the Pactor Theorem to determine whether g(x) is factor of /(x) in each of the
following cases
(III) /(x) = x³- 4x²+x+6. g(x) = x - 2
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Answer 1

Answer:

Given polynomial f(x)=x3−4x2+x+6   the factor of  g(x)=x−2

If x-2 is factor then x-2=0 or x=2

Replace x in  p(x) by 2 we get

f(x)=x3−4x2+x+6 

f(2)=(2)3−4(2)2+(2)+6

⇒f(2)=8−16+2+6

⇒f(2)=0

So f(x) is zero by g(x) =x-2 then g(x)=(x-2) is factor of  f(x)=x3−4x2−x+6 

Answer 2

Answer:

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