Question

2. Using the conversion factor [ Molar Mass = 1 Mole] solve the following problems using dimensional analysis. Keep track of your units!

a) Calculate the mass of 5.634 moles of HCN.
b) Calculate the moles of 257.354g of K2CrO4
c) Calculate the mass of 0.467 moles of CaBr2
d) Calculate the moles of 12.354 grams of C6H12O6.
e) Calculate the mass of 8.26 mmoles of KClO4
f) Calculate the moles of 35.7 milligrams of Sr(NO3)2

Answer 1

Answer:

a) pressure

c) mass become zero.

d) density become zero,

Direction: (Q. No.19 to 2 No.22)

The questions given below consists of an Assertion and the Reason. Use the following key to choose

the appropriate answer.

Option A: If both assertion and Reason are CORRECT and reason is the CORRECT explanation

of the assertion

Option B: If both Assertion and Reason are CORRECT, but the reason is NOT THE CORRECT

explanation of the assertion.

Option C: If assertion is CORRECT but reason is INCORRECT.

Option D: If assertion is INCORRECT but reason is CORRECT.

Option E: If both assertion and reason are INCORRECT.

Explanation:

Answer 2

The answers are 152.260g, 1.325 moles, 43.592g, 0.06857 moles, 1144.41g, 0.00016 moles respectively.

Molar mass (M) : It is the mass of a chemical compound divided by its amount of substance measured in moles.

It is defined as

$MB = m/nB$  [where m = total mass of a sample of pure substance , nB = amount of substance B given in moles.]

a) Mass of 5.634 moles of HCN = 152.260g

b) The moles of 257.354g of K2CrO4 = 1.325 moles

c) The mass of 0.467 moles of CaBr2 = 43.592g

d) The moles of 12.354 grams of C6H12O6 =0.06857 moles

e) The mass of 8.26 moles of KClO4 = 1144.41g

f) The moles of 35.7 milligrams of Sr(NO3)2 = 0.00016 moles

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