(2) Using the measures given in the figure, find the area of ABCD.
А
Solution :
6 cm
B
M
5 cm
12 cm
C
PLEASE SOMEONE GIVE ANSWER
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Area of ABCD
= area of ∆BAD + area ∆BCD
= ( AD × AB )/2 + ( DC × BT )/2
= ( 9 × 40 )/2 + ( 60 × 13 )/2
= 9 × 20 + 30 × 13
= 180 + 390
= 570 m²
Therefore,
Area of the ∆ABCD = 570 m²
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