Question

2. Value of sec 26° -cot64° is:
(a) 1
(b)-1
(co
(d)2​

Answer 1

Answer:

ur question is incomplete it should have been sec square 26° - cot 64° = sec square 26° - cot square (90 - 64°) = sec^2 26° - tan ^2 26° = 1 ( as 1 + sec^2 = tan^2)

Answer 2

(d)2 Is the answer you DEFENITELY REQUIRED