(2) Verify that points P(-2, 2), Q(2, 2) and
R(2, 7) are vertices of a right angled triangle.
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Given,
P(−2,2)
Q(2,2)
R(2,7)
⇒∣PQ∣=
(−2−2)
2
+(2−2)
2
=
(4)
2
=4units
⇒∣PR∣=
(−2−2)
2
+(2−7)
2
=
(4)
2
+5
2
=
16+25
=
41
units
⇒∣PQ∣=
(2−2)
2
+(2−7)
2
=
(5)
2
=5units
we can clearly see that
⇒∣PR∣
2
=∣PQ∣
2
+∣QR∣
2
( Pythagoras theorem )
since ∣PQ∣
2
=16
and ∣QR∣
2
=25
∴∣PQ∣
2
+∣QR∣
2
=16+25=41
and we have ∣PR∣=
41
∴∣PR∣
2
=41units
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