2. Verify whether 1 and -1 are zeroes of the polynomial x2 - 1 or not.
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p(x) = x² - 1
p(1) = (1)² - 1
= 1 - 1
= 0
p(-1) = (-1)² - 1
= 1 - 1
= 0
Therefore, both 1 and -1 are the zeroes of the polynomial x² - 1
Hope it helps.....
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