Question

2 volumes of a2, 5 volumes of b2 on combining forms 2 volumes of gaseous compound molecular formula of compound is​

Answer 1

Answer:

$a_2 b_5$

Explanation:

First of all, let us consider the Gay-Lussac's Law:

Let us consider a chemical reaction given as:

$pP_{(g)} + qQ_{(g)} \bold{\rightarrow} rR_{(g)} + sS_{(g)}$

P, Q , R and S all are gases.

The ratio of volumes of P:Q:R:S will be  p:q:r:s provided that they are measured at the same temperature and pressure.

where p, q, r and s are whole numbers .

Applying the above rule in the given conditions, the chemical reaction will be:

$2a_2+5b_2\rightarrow 2C$

Here, we have to find the molecular formula for C in terms of a and b.

If we see there are 4 atoms of a used,

10 atoms of b used.

Balancing the equation, there must be 4 atoms of a and 10 atoms of b in the product of chemical reaction.

Let the formula for C is $a_xb_y$

So, Number of atoms of a in product:

2 \times x = 4

x = 2

And, Number of atoms of a in product:

2 \times y = 10

y = 5

So, the balanced reaction is:

$2a_2+5b_2\rightarrow 2a_2 b_5$

So, the formula of chemical compound is $a_2 b_5$.