Question

 (2+w+w2)3-(1-3w+w2)3 = 65​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The value of w is 1

Solution:

$\Rightarrow (2+w+w 2)^{3}-(1-3 w+w 2)^{3}=65$

$\Rightarrow \left(1+1+w+w^{2}\right)^{3}-\left(1+w-4 w+w^{2}\right)^{3}=65 \\\\\Rightarrow \left(1+\left(1+w+w^{2}\right)\right)^{3}-\left(\left(1+w+w^{2}\right)-4 w\right)^{3}=65 \\\\\Rightarrow (1+0)^{3}-(0-4 w)^{3}=65$

$\left(a s\left(1+w+w^{2} \right)=0\right)$        

$\Rightarrow 1-(-4 w)^{3}=65 \\\\\Rightarrow 1+64 w^{3}=65 \\\\\Rightarrow 64 w^{3}=64 \\\\\\Rightarrow w^{3}=1$