Question

2 Walking at 3/4 of her usual speed, Richa is getting 5/4 hours late than her usual time to reach the finishing line. What is
the usual time that Richa takes to cover this distance?​

Answer 1

Answer: The time she used to take to travel the distance should be (15/4)hours, which can also be written as 3¾hours.

Step-by-step explanation:

Let her usual speed be Xkm/h

Let her usual time be T hours,

Let her usual distance be D.

Thus;

The equation for her usual journey can be written as,

Xkm/h × T hours = Dkm

Her new journey can be denoted as,

¾Xkm × (T+5/4) hours = Dkm.

Since the distance for the two equation are the same, let's bring the two equation together;

X × T = ¾X × (T+5/4)

X•T=¾X × (4T+5)/4

X•T=(3X × (4T+5))÷16

16(X•T) = 3X × (4T+5)

16(X•T)÷3X = 4T+5

16T÷3 = 4T+5

16T=3(4T+5)

16T=12T+15

16T-12T=15

4T=15

T=15/4=3¾

Get this, we should be able to calculate our distance and speed ratio.

From our first equation,

X × T = D

X × 15/4 = D

15X=4D

X/D=4/15

:- The ratio of speed to distance should is 4:15.

Answer 2

Answer:

15/4 hours

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