2 Walking at 3/4 of her usual speed, Richa is getting 5/4 hours late than her usual time to reach the finishing line. What is
the usual time that Richa takes to cover this distance?
Answers
Answer: The time she used to take to travel the distance should be (15/4)hours, which can also be written as 3¾hours.
Step-by-step explanation:
Let her usual speed be Xkm/h
Let her usual time be T hours,
Let her usual distance be D.
Thus;
The equation for her usual journey can be written as,
Xkm/h × T hours = Dkm
Her new journey can be denoted as,
¾Xkm × (T+5/4) hours = Dkm.
Since the distance for the two equation are the same, let's bring the two equation together;
X × T = ¾X × (T+5/4)
X•T=¾X × (4T+5)/4
X•T=(3X × (4T+5))÷16
16(X•T) = 3X × (4T+5)
16(X•T)÷3X = 4T+5
16T÷3 = 4T+5
16T=3(4T+5)
16T=12T+15
16T-12T=15
4T=15
T=15/4=3¾
Get this, we should be able to calculate our distance and speed ratio.
From our first equation,
X × T = D
X × 15/4 = D
15X=4D
X/D=4/15
:- The ratio of speed to distance should is 4:15.
Answer:
15/4 hours
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