Question

2 Weite
duaduatic polynom.
Sum of whose zerods
2d and product in
is​

Answer 1

Answer:

x ^2 - 2 \sqrt{3x} + 2

Step-by-step explanation:

Sum of zeroes =2

3,Product =2

⇒ Using, sum of zeroes =− coefficient of term x.

⇒ Product of zeroes = coefficient of constant term.

⇒ Quadratic polynomial can be =x ^2 - 2 \sqrt{3x} + 2