Question

2. What could be the final temperature of a
mixture of 100 g of water at 90°C and 600g
of water at 20°C.
​

Answer 1

Explanation:

100 × S × ( 90° - T ) = 600 × S × ( T- 20° )

(90° -T) = [600 × S × (T-20°)] / (100 × S)

⇒ 90° - T = 6(T - 20°)

⇒ 90° - T = 6T - 120

⇒ 120 +90 = 7T

7T = 210

T = 210/7

T = 30°

Answer 2

Answer:

hii naanum tamizan dha

pls pls mark it as brainlest answer