Question

2. What is nature of the roots of the quadratic equation 4xsquare + 4 root3x + 3 = 0​

Answer 1

Answer:

4x²+4√3x + 3 = 0

here , a = 4 , b = 4√3 , c = 3 (by comparing it with general form)

∆= b²- 4ac = (4√3)² - 4(4)( 3)= (16×3) - 48

= 48 - 48 =

since ∆ = 0

roots of the given quadratic equation are real and equal.

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