Question

2. What is the average (arithmetic mean) of the
positive integers from 1 to 100 inclusive?
(A) 40
(B) 49.5
(C) 50
(D) 50.5​

Answer 1

Answer:

Sum of AP is given by, {n * (a + l) /2} [Where a = first term, n = number of terms, l = last term.] = 100 * (1 +100)/2 = 50 * 101. Required Average = (50 *101)/100 = 50.5.

Answer 2

To find mean:-

(1+2+3+4+5+6+7+8+9+10+11+12+...100)/100

=>5050/100

=>50.5

Hope it helos you...