2. What is the distance travelled by light in vacuum
during the time interval 1/299,792,458 of a sec-
ond? (Assume c = 2.99792458 x 108 m/s)
options:
(a) 1 cm (b) 1 mm (c) lm (d) 1 km
I need explanations please
Answers
Answered by
1
Explanation:
distance=speed*time
=1/299792458*2.99792458*108
=1/299792458*299792458*10(8-8)
=1m
becoz, all the units is in SI unit therefore answer will also be in SI unit.
Similar questions
Business Studies,
5 months ago
English,
5 months ago
English,
9 months ago
Physics,
9 months ago
Biology,
1 year ago