Physics, asked by resmi2397, 9 months ago

2. What is the distance travelled by light in vacuum
during the time interval 1/299,792,458 of a sec-
ond? (Assume c = 2.99792458 x 108 m/s)
options:
(a) 1 cm (b) 1 mm (c) lm (d) 1 km

I need explanations please ​

Answers

Answered by Anonymous
1

Explanation:

distance=speed*time

=1/299792458*2.99792458*108

=1/299792458*299792458*10(8-8)

=1m

becoz, all the units is in SI unit therefore answer will also be in SI unit.

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