Question

2. What is the eleventh term of the geometric sequence 3, 6, 12, 24, ...?

Answer 1

Answer:

6141

Step-by-step explanation:

Given GP is 3,6,12,24,....

Here first term ,a=3 and common ratio ,r=2

S

n

=

r−1

a

1

(r

n

−1)

S

11

=

(2)−1

3((2)

11

−1)

=

1

3((2)

11

−1)

=6141

it's the sum of eleventh term of the geometric sequence