Question

2) What is the nature of roots
of quadratic equation
3x2-5x+3=0​

Answer 1

Answer:

3x

2

+2

5

−5=0

a=3,b=2

5

,c=−5

Discriminant: =b

2

−4ac

=(2

5

)

2

−4(3)(−5)

=20+60=80>0

Since, b

2

−4ac>0⇒ roots are real and distinct.

Answer 2

Answer:

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Step-by-step explanation:

3x2 – 5x + 7 = 0

Comparing the above equation with ax2 + bx + c = 0, we get

a = 3, b = -5, c = 7

∴ ∆ = b2 – 4ac

= (-5)2 -4 × 3 × 7

= 25 – 84

∴ ∆ = -59

∴ ∆ < 0

∴ Roots of the given quadratic equation are not real.