Question

2. What is the perpendicular distance between the force and the turning
point if a force of 25 N produces a moment of force of 12.5 Nm?
​

Answer 1

Given

• Force = 25 N
• Moment = 12.5 Nm

To Find

• Perpendicularly Distance

Solution

● τ = rF sinθ

✭ Simplifying the formula :

→ τ = rF sinθ

→ τ = (F) (r sinθ)

━━━━━━━━━━━━━━━━━━

✭ Perpendicular Distance :

→ τ = F × d

→ 12.5 = 25 × d

→ 12.5/25 = d

→ Perpendicular Distance = 0.5 m

∴ The perpendicularly distance from the pivot point is 0.5 m

━━━━━━━━━━━━━━━━━━

Know More

• Moment is a force Applied about a fixed axis.
• The greater the perpendicular distance the easier it is to move the body.
• An example for moment would be the opening of a door.

Answer 2

Given

Force = 25 N

Moment = 12.5 Nm

To Find

Perpendicularly Distance

Solution

● τ = rF sinθ

✭ Simplifying the formula :

→ τ = rF sinθ

→ τ = (F) (r sinθ)

━━━━━━━━━━━━━━━━━━

✭ Perpendicular Distance :

→ τ = F × d

→ 12.5 = 25 × d

→ 12.5/25 = d

→ Perpendicular Distance = 0.5 m

∴ The perpendicularly distance from the pivot point is 0.5 m