Question

2)
What is the sum of the first 10 terms of an A.P. 41, 36, 31, 26,
a) 635 b) 185
c) 200
d) 600​

Answer 1

Answer:

answer

Step-by-step explanation:

provied: tn = a+ n - 1 x d

tn= 10 , a= 14 , n = 10, d= -5

tn = 41 + 10 - 1 x -5

tn = 41+ 9x-5

tn= 41 + 45

tn = 86