Question

2] what is the sum of the first 10 terms of AP 41,36,31,
26.

​

Answer 1

Answer:

188

Step-by-step explanation:

First ten terms

41,36,31,26,21,16,11,6,1,-1.

Please follow if u like

Answer 2

Step-by-step explanation:

here a = 41, d = 36-41 => -5, n = 10

S10 = n/2 [ 2a + (n-1)d ]

=> S10 = 10/2 [ 2*41 + 10-1)*(-5) ]

=> 5 [ 82 + 9(-5) ]

=> 5 [ 82 - 45 ]

=> 5 [ 37 ]

=> 185

therefore sum of first 10 terms S10 = 74