2. What is the total surface area of a cone having radius r/2 and height 21?
Answers
Answer:
The total surface area of cone is \frac{22}{7} \times \frac{r}{2} \times \sqrt{21^2+(\frac{r}{2})^2}+\frac{22}{7} (\frac{r}{2})^2
7
22
×
2
r
×
21
2
+(
2
r
)
2
+
7
22
(
2
r
)
2
Step-by-step explanation:
Radius of cone = \frac{r}{2}
2
r
Height of cone = 21 cm
Total surface area of cone = \pi r \sqrt{h^2+r^2}+\pi r^2πr
h
2
+r
2
+πr
2
Total surface area of cone =\frac{22}{7} \times \frac{r}{2} \times \sqrt{21^2+(\frac{r}{2})^2}+\frac{22}{7} (\frac{r}{2})^2
7
22
×
2
r
×
21
2
+(
2
r
)
2
+
7
22
(
2
r
)
2
Hence The total surface area of cone is \frac{22}{7} \times \frac{r}{2} \times \sqrt{21^2+(\frac{r}{2})^2}+\frac{22}{7} (\frac{r}{2})^2
7
22
×
2
r
×
21
2
+(
2
r
)
2
+
7
22
(
2
r
)
2
#Learn more:
The radius of the base of the cone is 9 cm and its height is 40cm.What is the curved surface area ??? what is it's total surface area???
https://brainly.in/question/2927894
Answer:
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Step-by-step explanation:
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