2. What is the value of k if (k,5) is the solutions of the
simultaneous equations 4x+3y=19 and 4x-3y=-11
(A) -1/3 (B) 1 (C) 4 (D) 5
Answers
Answered by
4
Answer:
4x+3y=19--------(1)
4x-3y=-11---------(2)
Now, it is given that (k, 5)is the solution of eq. 1and 2
Now, taking k=x
5=y
Put the value of x and y in equation. 1
=>4(k)+3(5)=19
=>4k+15=19
=>4k=19-15
=>4k=4
=>k=1
SIMILARLY TO CONFIRM THE VALUR OF k PUT THE VALUE OF x and yIN EQUATION 2
HENCE,ANS =(B) 1
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Answered by
2
Step-by-step explanation:
Consider the given equations.
4x+ky+8=0 ……. (1)
2x+3y+7=0 …… (2)
The general equations,
a
1
x+b
1
y+c
1
=0
a
2
x+b
2
y+c
2
=0
Therefore,
a
1
=4,b
1
=k,c
1
=8
a
2
=2,b
2
=3,c
2
=7
Since, the condition of unique solution is
a
2
a
1
=
b
2
b
1
Therefore,
2
4
=
3
k
3
k
=2
k
=6
Hence, k value is 1
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