2) What maximum height a stone will
reach if it is thrown upwords with a
velocity of 20m/sec?(g = 10m/sec
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A stone is thrown vertically upward with a velocity of 20 meter/second. What is the maximum height reached by the stone?
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I'm sure this is homework, but oh well I guess.
height=Vinitialt−12gt2
So you need to determine the time it takes first.
V=Vinitial−gt
At its peak height velocity equals zero, so
0=20−9.8t →→
−20=−9.8t →→
−20−9.8=t
So
t=2.04 sec.
Now that we have the time:
h=20×2.04−129.8×2.042
h=40.8−20.39184
So,
h=20.41 m.
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