Question

2.) What should be added to the
Polynomial x^2+5 for it to leave 3
remainder when divided by x+3
​

Answer 1

Answer:

7

Step-by-step explanation:

when you divide x²+5 by x+3 it leaves remainder -4.

so by adding 7 we will get 3 as remainder.

Answer 2

There are infinity solutions. If we add a polinomial f (x) for x^2 + 5, and g (x) is the quoitient. Then,

X^2+5+f (x) = (x+3)g (x) + 3

Sub x =-3

(-3)^2+5+f (-3)=0+3

9+5+f (-3)=3

f (-3)=-11

Therefore all functions such f (-3)=-11 can be added to x^2+5 to give a remainder 3 when divided by x+3.

If a integer need to be added that must be -11.