Question

2. What should be added to (x-4) (x+6) to get the product (x-3)(x-8)?​

Answer 1

Answer:

So, it is clear that (-x) should be added to (x-4) (x-6) to get the product (x-3) (x-8).

Step-by-step explanation:

follow me please

Using the identity (x+a)(x+b)=x

Using the identity (x+a)(x+b)=x 2

Using the identity (x+a)(x+b)=x 2 +(a+b)x+ab,

Using the identity (x+a)(x+b)=x 2 +(a+b)x+ab, we get (x+8)(x−4)=x

Using the identity (x+a)(x+b)=x 2 +(a+b)x+ab, we get (x+8)(x−4)=x 2

Using the identity (x+a)(x+b)=x 2 +(a+b)x+ab, we get (x+8)(x−4)=x 2 +(8−4)x+8×(−4)=x

Using the identity (x+a)(x+b)=x 2 +(a+b)x+ab, we get (x+8)(x−4)=x 2 +(8−4)x+8×(−4)=x 2

Using the identity (x+a)(x+b)=x 2 +(a+b)x+ab, we get (x+8)(x−4)=x 2 +(8−4)x+8×(−4)=x 2 +4x−32.

Answer 2

Answer:

-13x+48

Step-by-step explanation:

(x-4) (x+6)

=x²+6x-4x-24

=x²+2x-24

and (x-3)(x-8)

=x²-8x-3x+24

=x²-11x+24

Now let x²+2x-24+ P=x²-11x+24

P=x²-11x+24-(x²+2x-24)

=x²-11x+24-x²-2x+24

=-13x+48