Question

2. What will be the altitude if diagonals of rhombus are 8 cm and 15 cm.​

Answer 1

The altitude of rhombus is 0.142 m

Step-by-step explanation:

Let ABCD is a rhombus where AC and BD are diagonals.

AC =15 cm

BD = 8 cm

Properties: Diagonals of a rhombus bisects at right angle.

Hence, OD = 4 cm, OC = 15/2 = 7.5 cm

In right triangle OCD, applying Pythagoras theorem,

$CD=\sqrt{7.5^2+4^2}\\\\CD=\sqrt{72.25}\\\\CD=8.5}$

Hence, base of the rhombus is $b=8.5$

Area of rhombus is given by

$A=\frac{1}{2}(8\times15)\\\\A=60m^2$

Therefore, altitude of rhombus is given by

$h=\frac{A}{b}\\\\h=\frac{8.5}{60}\\\\h=0.142 m$

#Learn More:

Find the area of rhombus whose side are of 10m and its altitude is 6m.If one of its diagonal is 5 m long. What is the length of the other diagonal?​

https://brainly.in/question/9253542