Question

2. When a car of mass 1200 kg is moving with a
velocity of 15 ms on a rough horizontal road,
its engine is switched off. How far does the
car travel before it comes to rest if the
coefficient of kinetic friction between the road
and tyres of the car is 0.5? (g=10ms-2)
$22.5$
$22$
​

Answer 1

Answer:

As we know that friction force always oppose the motion and want to rest the object. We know that the final speed of car will be zero. So after 22.5 m the car will stop

Explanation:

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Answer 2

Answer:

22.5m distance it will travel