Question

2. When four hydrogen nuclei combine to form a
helium nucleus in the interior of sun, the loss in
mass is 0.0265 a.m.u. How much energy is
released ?
Ans. 24.7 MeV​

Answer 1

Answer:

Solution. Given that Δm = 0.0265 a.m.u. 1 a.m.u. liberates 931.5 MeV of energy

Answer 2

Answer:

24.7

Explanation:

MeV

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