Question

2. When the rectangular metal tank is filled to the top with an
unknown liquid, as observer with eyes level with the top of
the tank can just see the corner E: a ray that refracts towards
the observer at the top surface of the liquid is shown. The
refractive index of the liquid will be​

Answer 1

Answer:

1.2

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Answer 2

Concept: Refractive index is the ratio of the speed of light in the lesser density medium to the speed of light in the greater density medium.

Given: The height of the tank (P) =4 cm

The length of the tank (B) =3 cm

Find:

Solution: By using Pythagoras theorem

$H^{2} =P^{2} +B^{2}$

     = $4^{2}+ 3^{2}$

      = 16+9

      = 25

$H^{2}$=25

H=$\sqrt{25}$

H=5 cm

Refractive index= $\frac{1}{sinx}$

                          =$\frac{1}{\frac{P}{H} }$

                          =$\frac{H}{P}$

                          =$\frac{5}{4}$

                          = 1.25

Final answer: Refractive index of the liquid will be​ 1.25.

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