Question

2
Which alkyl free radical is the most stable?
ut of
Select one:
Jestion
O a
Methyl
Ob
Primary
Ос.
Secondary
Od
Tertiary
3
How many nodes are present in V2 of 1,3-butadiene?​

Answer 1

Answer:

Solution

Correct option is

D

tertiary

Electron poor species are stabilized by neighboring atoms that can donate electron density. The most common way to interpret rich neighbors here is the observation that increasing the number of alkyl groups on the carbon bearing the free radical increases its stability.  

Radical stability increases in the order methyl < primary < secondary < tertiary.  

Hence, option D is correct.

Explanation: