2. Which of the following quadratic equation describe the speed of Raj's car?
a) x² - 5 X - 500 = 0
b) x² + 4x - 400 = 0
c) x² + 5x - 500 = 0
d) x² - 4x + 400 = 0
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Complete Question :- Refer to image .
Answer :-
→ speed of raj car = x km/h .
→ speed of ajay car = 5 km faster than speed of raj car = (x + 5) km/h .
so,
→ Distance cover by ajay in 2 hours = 2(x + 5) km. (Ans.i)
now,
→ time taken by raj to cover 400 km = D/S = (400/x) hours .
and,
→ time taken by ajay to cover 400km = D/S = 400/(x + 5) hours .
A/q,
→ 400/x - 400/(x + 5) = 4
→ 400{1/x - 1/(x + 5)} = 4
→ (x + 5 - x)/x(x + 5) = 1/100
→ x² + 5x = 5 * 100
→ x² + 5x - 500 = 0 (c) (Ans.ii)
solving this we get,
→ x² + 25x - 20x - 500 = 0
→ x(x + 25) - 20(x + 25) = 0
→ (x + 25)(x - 20) = 0
→ x = (-25) or 20 , since speed cant be in negative .
therefore, speed of raj's car is 20 km/h . (a) (Ans.iii)
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