2 women and 5 men
can together
finish a work
in 4 days while
3 womon
and 6 men can finish it in 3 days
find the time
taken by
1 women and 1 men alone?
Answers
Answer:
don't know please didi or bhai mai class 4 me hu
Answer:
Time taken by 1 man alone to finish the work =36 days
Time taken by 1 woman alone to finish the work =18 days
Step-by-step explanation:
Let the work done by man and woman per day be x and y respectively.
When the work is completed in 4 days
Since 5 men and 2 women complete the work in 4 days
therefore work done by 5 men and 2 women in 1 day = 1/4
∴5x+2y=1/4⟶eqn1
When the work is completed in 3 days
Since 6 men and 3 women complete the work in 3 days
therefore work done by 6 men and 3 women in 1 day = 1/3
∴6x+3y=1/3⟶eqn2
Multiplying by 3 in eqn1, we get
⇒15x+6y=3/4⟶eqn3
Multiplying by 2 in eqn2, we get
⇒12x+6y=2/3⟶eqn4
On subtracting eqn 4 from eqn 3, we get
15x+6y−12x−6y=3/4−2/3
⇒3x=1/12
⇒x=1/36
On substituting the value of x in eqn2, we get
⇒6×1/36+3y=1/3
⇒3y=1/3−1/6
⇒y=1/18
Thus,
work done by 1 man in 1 day =1/36days
∴ Time taken by 1 man alone to finish the work =36 days
work done by 1 woman in 1 day =1/18 days
∴ Time taken by 1 woman alone to finish the work =18 days
hope it helped you