2 women and 5 men can together finish an embroidery work in 4 days, while 3 women and 6 men can finish it in 3 days . Find the time taken by 1 women alone to finish the work, also that taken by 1 man alone.
Answers
The time taken by woman to complete the work be x days and by man be y days.
2 women and 5 men can together finish an embroidery work in 4 days.
3 women and 6 men can finish the same work in 3 days.
⇒ 2/x + 5/y = 1/4
⇒ (2y + 5x)/xy = 1/4
⇒ 4(2y + 5x) = xy
⇒ 8y + 20x = xy...........(1)
On the other hand, 3 women and 6 men can finish it in 3 days.
⇒ 3/x + 6/y = 1/3
⇒ (3y + 6x)/xy = 1/3
⇒ 3(3y + 6x) = xy
⇒ 9y + 18x = xy............(2)
On multiplying (eq 1) with 9 and (eq 2) with 8 we get,
⇒ 72y = 9xy - 180x...........(3)
⇒ 72y = 8xy - 144x...........(4)
On comparing we get,
⇒ 9xy - 180x = 8xy - 144x
⇒ 9xy - 8xy = - 144x + 180x
⇒ xy = 36x
⇒ y = 36 days
Substitute value of y in (eq 1)
⇒ 8(36) + 20x = 36x
⇒ 288 = 36x - 20x
⇒ 288 = 16x
⇒ x = 18 days
Woman alone can finish the work in 18 days and man alone in 36 days.
Heya !!
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Let 1 woman can finish the embroidery work in 'x' days and 1 man can finish it in 'y' days.
A woman's one day work = 1/x
and a man's one day work = 1/y
A.T.Q.
2/x + 5/y = 1/4 and
3/x + 6/y = 1/3
Let 1/x = a and 1/y = b
Now, 2a + 5b = 1/4 _(1)
and 3a + 6b = 1/3 _(2)
Multiplying _(1) by 3 and _(2) by 2 and subtracting
6a + 15b = 1/4
6a + 18b = 1/3
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0 + 3b = 1/4 - 1/3
=> 3b = 1/12
=> b = 1/(12×3)
=> b = 1/36
Putting b = 1/36 in _(1)
2a + 5(1/36) = 1/4
=> 72a + 5 = 36/4
=> 72a + 5 = 9
=> 72a = 9 - 5
=> 72a = 4
=> a = 4/72
=> a = 1/18
Now, a = 1/x = 1/18
=> x = 18
And, b = 1/y = 1/36
=> y = 36
So, 1 woman can finish the embroidery work in 18 days and 1 man can finish the work in 36 days.
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Hope my ans.'s satisfactory.☺