Math, asked by desaiom1735, 10 months ago

2 women and 6 men together complete one embroidery in 4 days. 3 women and 6 men complete the same task in 3 days. So how long does it take for a woman to complete work independently and a man independently?​

Answers

Answered by sonabrainly
1

Answer:

Step-by-step explanation:

a similar question is there in NCERT

A woman's one day work = 1/x

and a man's one day work = 1/y

2/x + 5/y = 1/4 and

3/x + 6/y = 1/3

Let 1/x = a and 1/y = b

Now, 2a + 5b = 1/4 _(1)

and 3a + 6b = 1/3 _(2)

Multiplying _(1) by 3 and _(2) by 2 and subtracting

6a + 15b = 1/4

6a + 18b = 1/3

___________

0 + 3b = 1/4 - 1/3

=> 3b = 1/12

=> b = 1/(12×3)

=> b = 1/36

Putting b = 1/36 in _(1)

2a + 5(1/36) = 1/4

=> 72a + 5 = 36/4

=> 72a + 5 = 9

=> 72a = 9 - 5

=> 72a = 4

=> a = 4/72

=> a = 1/18

Now, a = 1/x = 1/18

=> x = 18

And, b = 1/y = 1/36

=> y = 36

So, 1 woman can finish the embroidery work in 18 days and 1 man can finish the work in 36 days.

Answered by himanshusharma12221
4

Answer:-

no. of days of women = 18 days

no. of days of man = 36 days

Step by Step explanation:-

Let 1 woman can finish the embroidery work in 'x' days and 1 man can finish it in 'y' days.

A woman's one day work = 1/x

and a man's one day work = 1/y

A.T.Q.

2/x + 5/y = 1/4 and

3/x + 6/y = 1/3

Let 1/x = a and 1/y = b

Now, 2a + 5b = 1/4 _(1)

and 3a + 6b = 1/3 _(2)

Multiplying _(1) by 3 and _(2) by 2 and subtracting

6a + 15b = 1/4

6a + 18b = 1/3

___________

0 + 3b = 1/4 - 1/3

= 3b = 1/12

= b = 1/(12×3)

= b = 1/36

Putting b = 1/36 in _(1)

2a + 5(1/36) = 1/4

= 72a + 5 = 36/4

= 72a + 5 = 9

= 72a = 9 - 5

= 72a = 4

= a = 4/72

= a = 1/18

Now, a = 1/x = 1/18

= x = 18

And, b = 1/y = 1/36

=> y = 36

So, 1 woman can finish the embroidery work in 18 days and 1 man can finish the work in 36 days

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