Question

2.Write a program to check a number is an Armstrong Number or not.Armstrong number: The sum of cubes of each digit is equal to the number itself​

Answer 1

Answer:

Answer:

import java.util.*;

class Armstrong

{

public void main ()

{

Scanner sc = new Scanner (System.in);

System.out.println("Enter a number: ");

int n = sc.nextInt();

int rem,rev = 0;

for(int i = n;i > 0;i/=10)

{

rem = i%10;

rev = rev+rem*rem*rem;

}

if(n == rev)

{

System.out.println("Armstrong Number");

}

else

{

System.out.println("Not Armstrong Number");

}

}

}

I hope you find it useful... If you have any query do comment, I will try to solve it...

Answer 2

Program: {JAVA}

import java.util.*;

public class Brainly

{

static void main()

{

Scanner sc=new Scanner(System.in);

int t,d,s=0,n,f=0;

System.out.println("Enter an integer:");

n=sc.nextInt();

t=n;

while(t!=0)

{

d=t%10;

s=s+d*d*d;

t=t/10;

}

if(s==n)

System.out.println("Armstrong Number");

else

System.out.println("Not an Armstrong Number");

}

}