Question

2. Write a Pythagorean triplet whose one member is.
(i) 6

Answer 1

Answer:

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Step-by-step explanation:

As we know 2m, m2+1 and m2−1 from a Pythagorean triplet for any number , As we know 2m, m2+1 and m2−1 from a Pythagorean triplet for any number , m>1

Let us assume 2m=6

Therefore, m =3

And m2+1=32+1=9+1=10

And m2−1=32−1=9−1=8

Test : 62+82=36+64=100=102

Hence the triplet is 6,8, and 10 Answer 

Answer 2

Answer:

Thus the required Pythagorean triplet is 6,8,10. Thus the required Pythagorean triplet is 14,48,50.

Step-by-step explanation:

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