Question

2. Write an algorithm to check year is leap year or not​

Answer 1

Explanation:

int main() {

int year;

year = 2016;

if (((year % 4 == 0) && (year % 100!= 0)) || (year%400 == 0))

printf("%d is a leap year", year);

else

printf("%d is not a leap year", year);

return 0;

}

Answer 2

Answer:

Explanation:

START

  Step 1 → Take integer variable year

  Step 2 → Assign value to the variable

  Step 3 → Check if year is divisible by 4 but not 100, DISPLAY "leap year"

  Step 4 → Check if year is divisible by 400, DISPLAY "leap year"

  Step 5 → Otherwise, DISPLAY "not leap year"

STOP