2. Write first four terms of the AP, when the first term a and the common difference d are given as follows: 6) a= 10, d=10 (ii) a = -2, d=0 (ii) a=4, d=-3 (iv) a=-1, da 2 (v) a=-1.25, d=-0.25
Answers
Answer:
An arithmetic progression is given by a,(a+d),(a+2d),(a+3d), .
where a= the first term, d= the common difference
(i) 10,10+10,10+2(10) and 10+3(10)=10,20,30 and 40
(ii) −2,−2+(0),−2+2(0) and −2+3(0)=−2,−2,−2 and −2 (this is not an A.P)
(iii) 4,4+(−3),4+2(−3) and 4+3(−3)=4,4−3,4−6 and 4−9=4,1,−2 and −5
(iv)−1,−1+(
2
1
),−1+2(
2
1
) and −1+3(
2
1
)=−1,−
2
1
,0 and
2
1
(v)−1.25,−1.25+(−0.25),−1.25+2(−0.25) and −1.25+3(−0.25)=−1.25,−1.50,−1.75 and −2.0
Answer:
An arithmetic progression is given by a,(a+d),(a+2d),(a+3d), .
where a= the first term, d= the common difference
(i) 10,10+10,10+2(10) and 10+3(10)=10,20,30 and 40
(ii) −2,−2+(0),−2+2(0) and −2+3(0)=−2,−2,−2 and −2 (this is not an A.P)
(iii) 4,4+(−3),4+2(−3) and 4+3(−3)=4,4−3,4−6 and 4−9=4,1,−2 and −5
(iv)−1,−1+(
2
1
),−1+2(
2
1
) and −1+3(
2
1
)=−1,−
2
1
,0 and
2
1
(v)−1.25,−1.25+(−0.25),−1.25+2(−0.25) and −1.25+3(−0.25)=−1.25,−1.50,−1.75 and −2.0